x^2-7x+10=(x-5)(x-4)

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Solution for x^2-7x+10=(x-5)(x-4) equation: 



x^2-7x+10=(x-5)(x-4)

We move all terms to the left:

x^2-7x+10-((x-5)(x-4))=0

We multiply parentheses ..

x^2-((+x^2-4x-5x+20))-7x+10=0



We calculate terms in parentheses: -((+x^2-4x-5x+20)), so:

(+x^2-4x-5x+20)

We get rid of parentheses

x^2-4x-5x+20

We add all the numbers together, and all the variables

x^2-9x+20

Back to the equation:

-(x^2-9x+20)



We add all the numbers together, and all the variables

x^2-7x-(x^2-9x+20)+10=0

We get rid of parentheses

x^2-x^2-7x+9x-20+10=0

We add all the numbers together, and all the variables

2x-10=0

We move all terms containing x to the left, all other terms to the right

2x=10

x=10/2

x=5

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